Integrand size = 24, antiderivative size = 25 \[ \int x \left (b+2 c x^2\right ) \left (a+b x^2+c x^4\right )^p \, dx=\frac {\left (a+b x^2+c x^4\right )^{1+p}}{2 (1+p)} \]
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Time = 0.01 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {1261, 643} \[ \int x \left (b+2 c x^2\right ) \left (a+b x^2+c x^4\right )^p \, dx=\frac {\left (a+b x^2+c x^4\right )^{p+1}}{2 (p+1)} \]
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Rule 643
Rule 1261
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int (b+2 c x) \left (a+b x+c x^2\right )^p \, dx,x,x^2\right ) \\ & = \frac {\left (a+b x^2+c x^4\right )^{1+p}}{2 (1+p)} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00 \[ \int x \left (b+2 c x^2\right ) \left (a+b x^2+c x^4\right )^p \, dx=\frac {\left (a+b x^2+c x^4\right )^{1+p}}{2 (1+p)} \]
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Time = 0.13 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.96
method | result | size |
gosper | \(\frac {\left (c \,x^{4}+b \,x^{2}+a \right )^{1+p}}{2+2 p}\) | \(24\) |
risch | \(\frac {\left (c \,x^{4}+b \,x^{2}+a \right ) \left (c \,x^{4}+b \,x^{2}+a \right )^{p}}{2+2 p}\) | \(34\) |
parallelrisch | \(\frac {x^{4} \left (c \,x^{4}+b \,x^{2}+a \right )^{p} c^{2}+x^{2} \left (c \,x^{4}+b \,x^{2}+a \right )^{p} b c +\left (c \,x^{4}+b \,x^{2}+a \right )^{p} a c}{2 c \left (1+p \right )}\) | \(70\) |
norman | \(\frac {a \,{\mathrm e}^{p \ln \left (c \,x^{4}+b \,x^{2}+a \right )}}{2+2 p}+\frac {b \,x^{2} {\mathrm e}^{p \ln \left (c \,x^{4}+b \,x^{2}+a \right )}}{2+2 p}+\frac {c \,x^{4} {\mathrm e}^{p \ln \left (c \,x^{4}+b \,x^{2}+a \right )}}{2+2 p}\) | \(80\) |
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Time = 0.32 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.32 \[ \int x \left (b+2 c x^2\right ) \left (a+b x^2+c x^4\right )^p \, dx=\frac {{\left (c x^{4} + b x^{2} + a\right )} {\left (c x^{4} + b x^{2} + a\right )}^{p}}{2 \, {\left (p + 1\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 201 vs. \(2 (19) = 38\).
Time = 104.63 (sec) , antiderivative size = 201, normalized size of antiderivative = 8.04 \[ \int x \left (b+2 c x^2\right ) \left (a+b x^2+c x^4\right )^p \, dx=\begin {cases} \frac {a \left (a + b x^{2} + c x^{4}\right )^{p}}{2 p + 2} + \frac {b x^{2} \left (a + b x^{2} + c x^{4}\right )^{p}}{2 p + 2} + \frac {c x^{4} \left (a + b x^{2} + c x^{4}\right )^{p}}{2 p + 2} & \text {for}\: p \neq -1 \\\frac {\log {\left (x - \frac {\sqrt {2} \sqrt {- \frac {b}{c} - \frac {\sqrt {- 4 a c + b^{2}}}{c}}}{2} \right )}}{2} + \frac {\log {\left (x + \frac {\sqrt {2} \sqrt {- \frac {b}{c} - \frac {\sqrt {- 4 a c + b^{2}}}{c}}}{2} \right )}}{2} + \frac {\log {\left (x - \frac {\sqrt {2} \sqrt {- \frac {b}{c} + \frac {\sqrt {- 4 a c + b^{2}}}{c}}}{2} \right )}}{2} + \frac {\log {\left (x + \frac {\sqrt {2} \sqrt {- \frac {b}{c} + \frac {\sqrt {- 4 a c + b^{2}}}{c}}}{2} \right )}}{2} & \text {otherwise} \end {cases} \]
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Time = 0.22 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.32 \[ \int x \left (b+2 c x^2\right ) \left (a+b x^2+c x^4\right )^p \, dx=\frac {{\left (c x^{4} + b x^{2} + a\right )} {\left (c x^{4} + b x^{2} + a\right )}^{p}}{2 \, {\left (p + 1\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.92 \[ \int x \left (b+2 c x^2\right ) \left (a+b x^2+c x^4\right )^p \, dx=\frac {{\left (c x^{4} + b x^{2} + a\right )}^{p + 1}}{2 \, {\left (p + 1\right )}} \]
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Time = 8.76 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.96 \[ \int x \left (b+2 c x^2\right ) \left (a+b x^2+c x^4\right )^p \, dx={\left (c\,x^4+b\,x^2+a\right )}^p\,\left (\frac {a}{2\,p+2}+\frac {b\,x^2}{2\,p+2}+\frac {c\,x^4}{2\,p+2}\right ) \]
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